Question 48482
Again, 6 courses.


So how many can be the first one? Answer is any of the six --> 6.
and how many could then be second? Answer is any of the remaining five (since one of the courses was chosen to be first) --> 5.
and third? Answer is 4.


etc


So altogether we have 6*5*4*3*2*1 which is 6!. You work it out.


Jon