Question 467094
cos (theta-(3pi/4))
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What you have here is a cosine function of the form: y=Acos(Bx-C) with A=amplitude, period=2π/B, and phase shift=C/B
For given cosine function, y=cos(x-3π/4)
Amplitude=1
B=1
Period=2π/1=2π
Phase shift=3π/4 to the right
Ans:
What you have here is a cosine function whose value varies from +1 to -1 over one period(2π), depending on what theta(x) is.