Question 467315
Sorry about this idiot
:
xy+2x+3y+6
____________   =       I can not figure out how to solve this problem. Thanks!

xy+2x+5y+10
:
Factor by factoring out the common term in two groups
{{{(x(y+2)+3(y+2))/(x(y+2)+5(y+2))}}}
:
We can factor out (y+2) leaving
{{{((x+3)(y+2))/((x+5)+(y+2))}}}
:
(x+2) will cancel, leaving
{{{(x+3)/(x+5)}}}