<PRE><B>Question 467197</B>
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The equation of a circle has both *[tex \Large x^2] and *[tex \Large y^2] terms with equal coefficients.


The equation of a hyperbola has both *[tex \Large x^2] and *[tex \Large y^2] terms with coefficients that have opposite signs.


If the graph has a radius, then it is a circle.


Polynomial functions do not have asymptotes.


That only leaves one possibility.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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