Question 48425
I need to find an equation of the line in Ax+By=C form that passes through the points (3, -2) and (5, 4) 
First, find the slope (m) using the slope formula:
m = (y2-y1)/x2-x1) [Plug-in the values]
m = (4-(-2))/5-3) = 6/2 = 3
.
Using the point-slope format:
(y-y1) = m(x-x1)
(y-4) = 3(x-5)[Plug-in the values]
y-4=3x-15 [Simplify]
y-4+4 = 3x-15+4 [Move all of the variables to one side of the equation]
y=3x-11
-3x+y = -11 [Standard for of a line]