Question 467090
There are several ways to solve this equation. I will show you one of them.

The first option is to isolate a variable in one of the equations, and then substitute it into the other equation. If we take the equation 2x-y=-6, we can isolate the variable 'y':

2x-y=-6
First, we subtract '2x' from both sides
2x-y-2x=-6-2x
the values of '2x' cancel out on the left side of the equation
-y=-6-2x
Next, we multiply both sides of the equation by -1
y=6+2x

Then, we can take this value for 'y' and plug it into the other equation:

5x+2y=-15
We substitute in our value for 'y'
5x+2(6+2x)=-15
After that, we can distribute the 2
5x+12+4x=-15
Then, we combine the like terms in the equation
9x=-27
Finally, we divide both sides by three
x=-3

After we have a value for 'x', we can substitute it into either of the original equations to find the value for 'y'.

2x-y=-6
We substitute our value of 'x' in
2(-3)-y=-6
Then, we can multiply
-6-y=-6
We add 6 to both sides of the equation
-y=0
We divide both sides by -1
y=0

So, our solution to the problem is (-3,0).