Question 467113
Let the height of triangle be x units, then its base will be 2x+2 units, and the 

area is {{{30=(1/2)(2x+2)x=(1/2)2(x+1)x=x^2+x}}}<=>{{{x^2+x-30=0}}}, solving the 

final equation we get x=5. To find the length of the base substitute x=5 at 2x+2,

and get base 2*5+2=12 units.