Question 467103
First we find the width of the rectangle {{{W=sqrt(50)=5sqrt(2)}}}cm.

We know that the area of rectangle is A=L*W, substituting {{{L=10sqrt(10)}}}, and

{{{W=5sqrt(2)}}} we get:{{{A=10sqrt(10)*5sqrt(2)=50sqrt(20)=100sqrt(5)cm^2}}}.