Question 467006
{{{u=log(9,x)}}}
<pre>
Erase the log and swap the two outer numbers,
leaving the base of the log as the base of
the exponent:

{{{x=9^u}}}

----------------------

To find {{{log(2,81)}}} use the change of base formula:

{{{log(OLD_BASE,A)= log(NEW_BASE,A)/log(NEW_BASE,OLD_BASE)}}}

We have logs base 10 on the calculator so we let the new base
be 10 and the old base be 2

{{{log(2,81)=log(10,81)/log(10,2)=1.908485019/0.3010299957=6.339850003}}} 

Edwin</pre>