Question 467001
Let the two consecutive integers be: {{{(a)}}} and {{{(a+1)}}},then:
{{{(a)(a+1) = 240}}} Simplify.
{{{a^2+a = 240}}} Subtract 240 from both sides.
{{{a^2+a-240 = 0}}} Solve by factoring.
{{{(a-15)(a+16) = 0}}} Apply the zero product rule.
{{{a-15 = 0}}} or {{{a+16 = 0}}} so that:
{{{a = 15}}} or {{{a = -16}}}
There are two answers to this problem:
1) Consecutive integers: 15 and 16.
2) Consecutive integers: -16 and -15.