Question 466853
**Note, log means log base 3**
{{{4*log((3x+5)) = 12}}}
Divide by 4 on both sides
{{{log((3x+5)) = 3}}}
Rewrite equation in exponential form
**Note: {{{e^x = y}}} <=> {{{x = ln(y)}}}**
{{{3x + 5 = 3^3}}} 
Because its log base 3, if it was log base 5 then it would be 5^3 on right side
3^3 = 3*3*3 = 27
{{{3x + 5 = 27}}}
Subtract 5 on both sides
{{{3x = 22}}}
Divide by 3 on both sides
{{{x = 22/3}}}