Question 466780
For x < 2;
1/(|x - 2|) + 1/(|2 - x|) = ? 
I got both terms multiplied by the denominator/denominator of the other term to get both of them to the same common denominator, mainly:
(|2 - x| + |x - 2|)/(|2 - x| * |x - 2|), but don't know how to proceed further
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If x < 2 |x-2| is always negative; so |2-x| = -(2-x) = x-2
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If x < 2, |2-x| is always positive; so |2-x| = 2-x
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So, if x < 2, 1/|x-2| + 1/|2-x|
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= 1/(x-2) + 1/(2-x)
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= [2-x+x-2]/[(x-2)(2-x)]
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= 0/[(x-2)(2-x)]
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= 0
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Cheers,
Stan H.