Question 466762
2^(3x+1)= 3^(x-2) 
(3x+1)*log(2) = (x-2)*log(3)
3x*log(2) + log(2) = x*log(3) - 2log(3)
x*log(8) - x*log(3) = -log(2) - log(9)
x*log(8/3) = -log(18)
x = -log(18)/log(8/3)
x =~ -2.9469