Question 466750

given:

the perimeter of a rectangle is {{{P=146in}}}


The length {{{L}}} exceeds the width {{{W}}} by {{{23in}}}

{{{L=W+23in}}}

{{{P=2(L+W)}}}

{{{146in=2(L+W)}}}...replace {{{L}}} with {{{W+23in}}}

{{{146in=2(W+23in+W)}}}

{{{146in/2=2(W+23in+W)/2}}}

{{{73in=2W+23in}}}

{{{73in-23in=2W}}}

{{{50in=2W}}}

{{{50in/2=W}}}

{{{W=25in}}}

{{{L=W+23in}}}..->....{{{L=25in+23in}}}.->....{{{L=48in}}}