Question 466703
i) {{{(2)^(x+1)+(2)^(x)=9}}}
{{{2^x(2^1 + 2^0) = 9}}}
{{{2^x*3 = 9}}}
{{{2^x = 3}}}
x*log(2) = log(3)
x = log(3)/log(2)
x =~ 1.58496
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ii) {{{(2)^(x-2)(3)^(x+2)=(6)^(x)}}}
(x-2)log(2) + (x+2)log(3) = x*log(6)
xlog(2) - log(4) + xlog(3) + log(9) = xlog(6)
x(log(2) + log(3) - log(6)) = log(4/9)
x*log(1) = log(4/9)
0 = log(4/9) --> no solution