Question 48277
y= -4x^2 +16x-12
-4(x^2-4x+4)=y+12-16
-4(x-2)^2 = y-4
(x-2)^2=-(1/4)(y-4)

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I need to graph y= -4xsquared +16x-12
vertex at (2,4)
axis of symmetry: x=2
y-intercept: (0,-12)
x-intercepts: 

*[invoke quadratic "x",-4,16,-12]
Cheers,
Stan H.