Question 466432
In 1993, the life expectancy of males in a certain country was 66.8 years.
 in 2000, it was 70.4 years.
 let E represent the life expectancy in year t and let t represent the number of years since 1993.
:
Find the slope
In 1993; x1=0 and y1=66.8
In 2000; x2=7 and y2=70.4
:
Find the slope (m) using the slope equation: m = {{{(y2-y1)/(x2-x1)}}}
m = {{{(70.4-66.8)/(7 - 0))}}} = {{{(3.6)/(7)}}} = 
:
Use the point/slope formula to write the equation; y - y1 = m(x - x1)
y - 66.8 = {{{3.6/7}}}(x - 0)
y = {{{3.6/7}}}x + 66.8
:
therefore:
The Linear function E(t) that fits the data is.
E(t)= {{{3.6/7}}}t + 66.8
:
Use the Function to predict the life expectancy of males in 2003.
This means t=10; substitute 10 for t in the equation
E(10)= {{{3.6/7}}}(10) + 66.8
E(10)= 5.1 + 66.8
E(10)~ 72 yrs is the life expectancy in 2003