Question 466563
coin jar there is a collection of nickels, dimes, and quarters which totals $4.05.
 There are twice as many quarters as nickels and 8 more dimes than nickels.
 How many coins of each kind are there?
:
Let n = no.of nickel
Let d = no. of dimes
let q = no. of quarters
:
Write an equation for each statement:
:
"coin jar there is a collection of nickels, dimes, and quarters which totals $4.05."
.05n + .10d + .25q = 4.05
:
"There are twice as many quarters as nickels"
q = 2n
:
"and 8 more dimes than nickels."
d = (n+8)
:
In the 1st equation, replace q with 2n, replace d with (n+8)
.05n + .10(n+8) + .25(2n) = 4.05
.05n + .10n + .8 + .50n = 4.05
.05n + .10n + .50n = 4.05 - 80
.65n = 3.25
n = {{{3.25/.65}}}
n = 5 nickels
:
I'll let you find d and q, check solutions in the total$ equation.