Question 466563
In Jose's coin jar there is a collection of nickels, dimes, and quarters which totals $4.05. There are twice as many quarters as nickels and 8 more dimes than nickels. How many coins of each kind are there?
...
let x=number of nickels
2x=number of quarters
x+8= number of dimes
.05x+.25(2x)+.1(x+8)=4.05
.05x+.5x+.1x+.8=4.05
.65x=3.25
x=3.25/.65=5
ans:
number of nickels=5
number of quarters=10
number of dimes=13