Question 48347
Steve traveled 200 miles at a certain speed. Had he gone 10mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.
let his speed be =x mph
speed at 10 mph faster=x+10 mph
time to go 200 miles
1.at normal speed =200/x
at faster speed =200/(x+10)
difference = 200[(1/x)-1/(x+10)]=200(x+10-x)/x(x+10)=1
2000=x^2+10x
x^2+10x-2000=0
(x+50)(x-40)=0
x=40 mph
x=