Question 466381
First we write the equation of the parabola in standard form.

f(x)=-(x^2+6x+2)=-(x^2+6x+9-9+2)=-(x+3)^2+7

The vertex of the parabola is (-3, 7).
The axis of symmetry is the line x=-3.
The y-intercept is (0, -2).
An additional point on the graph will be:(-6, -2).

{{{graph(400, 400, -10, 10, -10, 10, -x^2-6x-2)}}}