Question 466423
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Adding two prime numbers does NOT always result in an even number.  2 is prime and 3 is prime.  2 plus 3 is 5 and 5 is odd.


However, adding two odd numbers always results in an even number, so you can say that adding any two prime numbers that are GREATER THAN 2, results in an even number because all prime numbers greater than 2 are odd.  They have to be because if any prime number greater than 2 was an even number, it would have a factor of 2 and wouldn't be prime.


The *[tex \Large n]th odd number is *[tex \Large 2n\ -\ 1].  The *[tex \Large m]th odd number is *[tex \Large 2m\ -\ 1].


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (2n\ -\ 1)\ +\ (2m\ -\ 1)\ =\ 2n\ +\ 2m\ -\ 2\ =\ 2(n\ +\ m\ -\ 1)]


And the sum is divisible by 2 for all integers *[tex \Large n] and *[tex \Large m].  Any number divisible by 2 is even by definition.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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