Question 466404
You have to apply the "rules for logarithms"
log(1 + x) + log(2 + x) = 2 
we can rewrite the above as:
log(1 + x)(2 + x) = 2 
(1 + x)(2 + x) = 10^2 
expanding left side by FOILing:
2+3x+x^2 = 100
x^2+3x+2 = 100
x^2+3x-98 = 0
since the above can't be factored, you must apply the "quadratic formula" to get:
x = {8.51, -11.51}
You can throw out the negative solution (extraneous) leaving:
x = 8.51
.
Details of quadratic follows:
*[invoke quadratic "x", 1, 3, -98 ]