Question 466337
. A comittee of 10 women and 9 men is looking to create a 6 person committee. 
a. how many ways are there of choosing this committee?
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Ans: 19C6 = 19!/(13!*6!) = (19*18*...*14)/(1*2*...6) = 27,132
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b. How many ways are there of chosing 4 men and 2 women?
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Ans: [9C4*10C2] = 5670
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c. Whats the probability that it's selected with 4 men and 2 women?
Ans: 5670/27132 = 0.2090
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d. What is the probility that it's selected with 5 women and 1 man?
Ans: [10C5*9C1]/[19C5] = 0.0836
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Cheers,
Stan H.