Question 466327
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The perimeter of any rectangle is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P_o\ =\ 2l\ +\ 2w]


If you multiply each of the length and width by some arbitrary number *[tex \Large a], then the perimeter of your resized but similar rectangle is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P_n\ =\ 2al\ +\ 2aw\ =\ a(2l\ +\ 2w)\ =\ aP_o]


So multiplying each of the dimensions by *[tex \Large a] results in the new perimeter being *[tex \Large a] times the old perimeter.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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