Question 3351
s=(1)/(2)*gt^(2)


Since g is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
(1)/(2)*gt^(2)=s


Multiply (1)/(2) by gt^(2) to get (gt^(2))/(2).
(gt^(2))/(2)=s


Multiply each term in the equation by 2.
(gt^(2))/(2)*2=s*2


Simplify the left-hand side of the equation by canceling the common factors.
gt^(2)=s*2


Multiply s by 2 to get 2s.
gt^(2)=2s


Divide each term in the equation by t^(2).
(gt^(2))/(t^(2))=(2s)/(t^(2))


Cancel the common factor of t^(2) in (gt^(2))/(t^(2)).


g=(2s)/(t^(2))