Question 1644
I'm going to be real. This was hard...and confusing but here's what I did.

The Problem

3bx+9=4(3x-b)+2
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The Steps:
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Multiply 4 by each term inside the parentheses.

3bx+9=12x-4b+2


Since 12x contains the variable to solve for, move it to the left-hand side of the equation by subtracting 12x from both sides.

3bx+9-12x=-4b+2


Factor out the GCF of 3x from each term in the polynomial.

3x(b)+3x(-4)=-4b-7


Factor out the GCF of 3x from 3bx-12x.

3x(b-4)=-4b-7


Divide each term in the equation by (b-4).

(3x(b-4))/(b-4)=-(4b)/(b-4)-(7)/(b-4)

Simplify the left-hand side of the equation by canceling the common factors.


3x=-(4b)/(b-4)-(7)/(b-4)


Simplify the right-hand side of the equation by simplifying each term.

3x=(-4b-7)/(b-4)


Divide each term in the equation by 3.

(3x)/(3)=(-4b-7)/(b-4)/(3)


Simplify the left-hand side of the equation by canceling the common factors.

x=(-4b-7)/(b-4)/(3)


Simplify the right-hand side of the equation by simplifying each term.

x=(-4b-7)/(3(b-4))