Question 48335
|5-2x|>3 [There are two conditions that must be considered in problems with absolute values:  either x > 0 or x < 0]
|5-2x|>3 [First condition where x>+3]
5-2x>3 [Solve for x]
-5 + 5-2x>3-5
-2x>-2
-2x/-2<-2/-2 [Switch the sign when multiplying or dividing by a negative number]
x<1

.
|5-2x|>3 [Second condition where x<-3]
5-2x<-3
5-2x<-3 [Solve for x]
-5+5-2x<-3-5
-2x<-8
-2x/-2>-8/-2 [Switch the sign when multiplying or dividing by a negative number]
x>4

.
So, x<1 or x>4