Question 465771
*[tex \LARGE y^{c-d}]


Since c < d, it follows c-d < 0, regardless of whether c and d are positive or negative. To rewrite with a positive exponent, we reciprocate it, yielding


*[tex \LARGE \frac{1}{y^{-(c-d)}} = \frac{1}{y^{d-c}}]