Question 466252
x - 2 + x - 1


Sum of reciprocals
= 1/(x - 2) + 1/(x - 1) 
= (x - 1) / (x - 2)(x - 1) + (x - 2) / (x - 2)(x - 1) {got common denominator}


x - 1 + x - 2
-------------- {combined numerators over common denominator}
(x - 2)(x - 1)


2x - 3
-------------- {combined like terms in numerator}
(x - 2)(x - 1)
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