Question 466174
In quarters dimes and nickels equaling 24.15. find the number of each kind if there are twice as many nickels as quarters and five more dimes than nickels.
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Equations:
5n  + 10d  +  25q = 2415 cents
n = 2q
d = n+5
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Substitute for "q" and for "d"; solve for "n":
5n + 10(n+5) + 25(n/2) = 2415
10n + 20n+100 + 25n = 4830
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55n = 4730
n = 86 (# of nickels)
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q = n/3 = 43 (# of quarters)
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d = n+5 = 91 (# of dimes)
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Cheers,
Stan H.
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