Question 466086
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Hi,
Find the z-score for which 90% of the distributions's are lies between -z and z
NORMSINV(0.05)= 1.6449
{{{drawing(400,200,-5,5,-.5,1.5, graph(400,200,-5,5,-.5,1.5, exp(-x^2/2)), green(line(-1.6449,0,-1.6449,exp(-1.6449^2/2)),line(1.6449,0,1.6449,exp(-1.6449^2/2))),locate(4.8,-.01,z),locate(4.8,.2,z))}}}