Question 466005
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Hi,
z = (x-u)/s, 
x = zs + u
x = (2/3)10 +57.5
x = 64.17

z = (75-57.5)/10 = 1.75    NORMSDIST(1.75)= .9599  
 4% of candidates with an A

 mean 57.5, sd = 10  
Score of 20 nearly 4 sd left of mean...definitely an "out liar"