Question 464834
let width be x and length y, then
2x+2y=34
xy=60
solve the system
x=60/y
2(60/y)+2y=34
120/y+2y=34
120+2y^2=34y
{{{2y^2-34y+120=0}}}
{{{y^2-17y+60=0}}}
(y-5)(y-12)=0
y=5 and y=12
so the sides are 5 and 12 since 5*12=60