Question 465882
"Can you please show me how to expand y= 2(x-3)^2+7 into the general form y= ax^2+bx+c"


y = 2(x - 3)² + 7
y = 2(x - 3)(x - 3) + 7 {squared the binomial by multiplying it by itself}
y = 2(x² - 6x + 9 + 7 {used the foil method}
y = 2x² - 12x + 18 + 7 {used the distributive property}
y = 2x² - 13x + 25 {combined like terms}
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