Question 465873
<pre>
You have the vertex and y-intercept wrong.

Here is the model to follow:

f(x) = a(x - h)² + k 

has:

vertex: (h,k)

axis of symmetry: x = h

y-intercept: (0,ah²+k)

Domain: all real numbers (-&#8734;, &#8734;)

Range: 

if a > 0, range is [k, &#8734;)
if a < 0, range is (-&#8734;, k]


x-intercepts

a(x - h)² + k = 0

    a(x - h)² = -k

     (x - h)² = -k/a
                  ____
        x - h = ±<font face = "symbol">Ö</font>-k/a

                     ____
            x = h ± <font face = "symbol">Ö</font>-k/a

x intercepts are:
                ____
      (x - h - <font face = "symbol">Ö</font>-k/a, 0)

and 

                ____
      (x - h + <font face = "symbol">Ö</font>-k/a, 0)



Now substitute the proper numbers for a, h, k, in all those. 
[Don't let the clashing notation of h and h(x) confuse you, 
they are not the same at all. To avoid confusion use H(x) 
instead of h(x)].

Edwin</pre>