Question 465640
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
x+y+3z=-1
x+2y-2z=-2
4x+12y+kz=-11
D={{{(matrix(3,3,1,1,3,1,2,-2,4,12,k))}}}
D={{{(matrix(3,3,a1,b1,c1,a2,b2,c2,a3,b3,c3))}}} 
D = a1(b2c3-c2b3) - b1(a2c3-c2a3) + c1(a2b3-b2a3) 
 0 = (2k+24)-(k+8) + 3(4)
-28 = k