Question 465616
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Hi
Find EQ, in slope-intercept form, of the line that contains the points (-1, 8) and (4, 3)?
Using the point-slope formula, {{{m =(y[2] - y[1])/(x[2] - x[1])}}}
(-1, 8) 
 (4, 3)  m = 5/ -5 = -1
Using the standard slope-intercept form for an equation of a line y = mx + b  where m is the slope and b the y-intercept.  
  y = -x + b
  8 = 1 + b
  7 = b
 y = -x  + 7
{{{drawing(300,300,   -10,10,-10,10, grid(1),
circle(-1, 8,0.4),
circle(4, 3,0.4),
graph( 300, 300, -10,10,-10,10,0,-x+7 ))}}}