Question 465511
{{{(x^2- 1)/(x+1) = x - 1}}}.
Notice that if {{{x <> -1}}}, then we can cancel terms from the left-side of the equation, to get

{{{(x^2- 1)/(x+1) = ((x-1)(x+1))/(x+1) = x - 1}}},

which tells us that the equation is an IDENTITY as long as {{{x <> -1}}}.  

Hence the solution set is the set of all real numbers except -1.