Question 48194
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{{{ln(a + b) + ln(a - b) - 2 ln c}}}


Use logarithmic law: log a + log b = log ab

{{{ln(a + b) + ln(a - b) - 2 ln c  = ln (a+b)(a-b) - 2 ln c = ln (a^2-b^2) - 2 ln c}}}

Use logarithmic law: a log b = log (b^a)

{{{ln (a^2-b^2) - 2 ln c}}}

{{{ln (a^2-b^2) - ln (c^2)}}}

Use logarithmic law: log a - log b = log {{{(a/b)}}}

{{{ln (a^2-b^2) - ln (c^2)}}}

{{{ln ((a^2-b^2)/(c^2))}}}



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