Question 465365
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
In answer to Your reply: the standard slope-intercept form y = mx + b
(found by simply by expressing the linear equation in terms of y) 
is a powerful tool in graphing the Line.
1) the 'trailer'(b) tells us where the Line crosses the y-axis.(-4 for blue line)
2) the slope(m) tell us how the line slants. (m>0 slants right, m<0 slants left)
3) the value of slope m, tells us the steepness of the 'slant'
4) In this example slope m = 2 or 2/1, telling us, if we were to start at
the y-intercept point, going up 2 and over 1, gives us one more point on the line.
5) connect these points with a line and the graphing is complete.
*[tex \LARGE\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
straight line parallel to the graph of y=2x  Green
Lines would need to have identical slopes of  m = 2
c. 2x-y = 4 OR  {{{y = highlight(2)x-4}}}  Blue

{{{drawing(300,300,   -6, 6, -6, 6,grid(1),
circle(0, 0,0.3),
circle(1, 2,0.3),
circle(0, -4,0.3),
circle(1, -2,0.3),
graph( 300, 300, -6, 6, -6, 6,0,2x,2x-4))}}}