Question 465361
normal distribution has a mean of meu= 22 with sigma= 3. What score is needed to place in the top 14% of the distribution?
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Find the z-value with a left tail of 0.86
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InvNorm(0.86) = 1.0803
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score = 1.0803*3 + 22 = 25.24
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Cheers 
Stan H.