Question 465308
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Hi,
Let x,(x+1) and (x+2) represent the 3 consecutive integers 
Question states***
x(x+1)(x+2)= 120
x{x^2+3x+2) = 120
 x^3 + 3x^2 +2x - 120 = 0  |x = 4 a solution  64+48 + 8 -120 = 0
Integers are 4,5,6
CHECKING our Answer***
 4*5*6 = 120