Question 48179
A box contains 4 red and 5 green balls.  Three balls are drawn. The probability 2 red and 1 green are drawn are drawn is.

Draw the 2 red in 4C2 = 6 ways
Draw the 1 green in 5C1=5 ways
Draw 3 of any kind 9C3 = 9*8*7/1*2*3 = 84

Prob (2R and 1G)= #of ways to suceed / # of possible outcomes
= 6*5/84 = 15/42=5/14

Cheers,
Stan H.