Question 465213
Hi, Assuming this correctly represents the two equations
 2x+4y=12 
 3x+5y=14
{{{D[y]}}} = {{{(matrix(2,2,2,12,3,14))}}}   
|Note: referred to as the 'second' {{{A[x]}}} below, typo as the {{{A[y]}}}
*[invoke cramers_rule_2x2 2,4,12,3,5,14]