Question 465044
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30-60-90 right triangle.  Short leg is the vertical distance from Dolores' height of eye to the water below.  Sides are in proportion *[tex \Large \frac{1}{2}:\frac{\sqrt{3}}{2}:1].  So if the short leg is 50 feet, then the hypotenuse is 100 feet and the long leg (the desired distance) is *[tex \Large 50\sqrt{3}]


And next time, show Dolores a little respect -- capitalize her name.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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