Question 48147
Let’s say the width of the gravel path is X,
Then:
2*12 X +2* 5X + 4X2 = 138
4X2 + 34X –138 = 0
2X2 + 17X –69 = 0
(2X+23)(X-3) = 0
X= -23/2 or 3, X>0
Ans: X= 3