Question 465008
two cars start at the same point going opposite derections one travels 6mph faster than the other. in 4 houts they are 184 mile apart how fast were each going
.
Let x = speed of slower car
then
x+6 = speed of faster car
.
4x + 4(x+6) = 186
dividing both sides by 4:
x + x+6 = 46.5
2x+6 = 46.5
2x = 40.5
x = 20.25 mph (slower car)
.
faster car:
x+6 = 20.25+6 = 26.25 mph