Question 48148
{{{f(x)=x^2 + 0x -2}}}
{{{(-b/2a)}}} [Formula for finding the "x" value of the vertex]
.
a = 1
b = 0 
c = -2
.
{{{(-b/2a)}}}
(-0)/(2)(1)[Plug-in the values]
0 [The x valued of the vertex = 0]
.
{{{f(x)=0^2-2}}}[Plug (x=0) back into the function and solve for "y"]
y = -2 
.
(0, -2) [Values of the vertex]