Question 464963
First we set the equation {{{6x^2=23x-15}}} equal to zero:

{{{6x^2-23x+15=0}}}. To solve the equation we use the quadratic formula:

{{{x=(23+-sqrt(23^2-4*6*15))/(2*6)= (23+-sqrt(169))/12}}}. As you see we have

two solutions:{{{x=(23+13)/12=3}}} and {{{x=(23-13)/12=10/12=5/6}}}.